Anonim
takie fajne rzeczy mozna sobie zrobic z 1-testa...
i dodaje ze jest on tylko polproduktem!!!
wyprodukowanie jego jest proste jak ....
BOLDENONE CYPIONATE (fast acting EQ)
Step 1: 1-Test cyp is brominated in the 4 position with 2,4,4,6-tetrabromocyclohexa-2,5-dione in ether with catalytic HCl. The product is 4-bromo-1-testosterone cypionate. There are other methods to achieve this bromination as well but this one should work very cleanly with a minimum of side reactions.
Step 2: the bromide is eliminated to give the 4,5-double bond by stirring the above product in DBU for 10 to 20 minutes. The overall yield of bold cyp should be around 75 to 80%
METHANDROSTENOLONE (dbol)
Step 1: The bold cyp from above is stirred in boiling benzene with ethylene glycol and catalytic acid. A Dean-Stark trap should be used to remove water as it is formed. This protects the 3-one as an ethylene ketal.
Step 2: The above protected bold cyp is stirred in boiling methanol/water with NaOH to remove the cyp ester.
Step 3: The 17-OH is oxidized to a ketone with any of a variety of chromium VI reagents.
Step 4: The above 17-one is reacted with methyl magnesium iodide. The reaction is quenched with water and acid. Heating the mixture with the water and acid will remove the ethylene ketal as well, leaving you with methandrostenolone.
METHENOLONE CYPIONATE (Primobolin, although real primo is the enanthate, not the cypionate, I expect little difference in function.
Step 1: 1-Test cyp is reacted with tetramethyl dilithium pentacuprate (formed in-situ from CuI and meLi). The reaction is quenched with liquid bromine. The product is 2-bromo-1-methyl-DHT.
Step 2: The bromine is eliminated to give back the 1,2-double bond by stirring with DBU as in the synthesis of bold cyp. The product is methenolone cypionate.
MESTEROLONE (proviron)
1-Test base is reacted with tetramethyl dilithium pentacuprate (formed in-situ from CuI and meLi). The reaction is quenched with water to afford mesterolone in a single step.
OXANDROLONE (Anavar)
Step 1: Starting with 1-test base, the 3-one is protected as the ethylene ketal as in the above synthesis of methandrostenolone.
Step 2: The 17-OH is oxidized to a 17-one with chomium VI reagent.
step 3: The 17-methyl is attached with methyl magnesium iodide and the crude reaction mixture is treated with water and acid to quench the reaction and remove the ketal protecting group. The product is 17-methyl-1-test.
Step 4: the 17-methy-1-test is treated with ozone in methanol and then NaOH is added. This allows the purification of the intermediate by recrystallization of the sodium salt. The result is that the double bond is cleaved to give a carboxyolic acid (salt) on one side and an aldehyde on the other. The salt is dissolved in water and acidified to pH=4. NaBH4 is added to reduce the intermediate aldehyde. The resulting alcohol will spontaniously close with the carboxylic acid to give the desired lactone ring. The product is oxandrolone.
OXYMETHYLONE (Anadrol)
17-methyl-1-test from above is reduced with lithium in liquid ammonia. The ammonia is carefully evaporated under a dry N2 atmosphere to give a dry, crystalline enolate. The enolate is dissolved in dry THF and treated with N-formylmorpholine to give oxymethylone as the product.
DROMOSTANOLONE propionate (Masterone)
Step 1: 1-test base is reduced with lithium in liquid ammonia. The ammonia is carefully evaporated under a dry N2 atmosphere to give a dry, crystalline enolate. The enolate is dissolved in dry THF and treated with methyl iodide to install the 2-methyl group.
Step 2: the dromostanolone resulting from step 1 is esterified with propanoyl chloride and pyridine to afford the product, masterone.
i dodaje ze jest on tylko polproduktem!!!
wyprodukowanie jego jest proste jak ....
BOLDENONE CYPIONATE (fast acting EQ)
Step 1: 1-Test cyp is brominated in the 4 position with 2,4,4,6-tetrabromocyclohexa-2,5-dione in ether with catalytic HCl. The product is 4-bromo-1-testosterone cypionate. There are other methods to achieve this bromination as well but this one should work very cleanly with a minimum of side reactions.
Step 2: the bromide is eliminated to give the 4,5-double bond by stirring the above product in DBU for 10 to 20 minutes. The overall yield of bold cyp should be around 75 to 80%
METHANDROSTENOLONE (dbol)
Step 1: The bold cyp from above is stirred in boiling benzene with ethylene glycol and catalytic acid. A Dean-Stark trap should be used to remove water as it is formed. This protects the 3-one as an ethylene ketal.
Step 2: The above protected bold cyp is stirred in boiling methanol/water with NaOH to remove the cyp ester.
Step 3: The 17-OH is oxidized to a ketone with any of a variety of chromium VI reagents.
Step 4: The above 17-one is reacted with methyl magnesium iodide. The reaction is quenched with water and acid. Heating the mixture with the water and acid will remove the ethylene ketal as well, leaving you with methandrostenolone.
METHENOLONE CYPIONATE (Primobolin, although real primo is the enanthate, not the cypionate, I expect little difference in function.
Step 1: 1-Test cyp is reacted with tetramethyl dilithium pentacuprate (formed in-situ from CuI and meLi). The reaction is quenched with liquid bromine. The product is 2-bromo-1-methyl-DHT.
Step 2: The bromine is eliminated to give back the 1,2-double bond by stirring with DBU as in the synthesis of bold cyp. The product is methenolone cypionate.
MESTEROLONE (proviron)
1-Test base is reacted with tetramethyl dilithium pentacuprate (formed in-situ from CuI and meLi). The reaction is quenched with water to afford mesterolone in a single step.
OXANDROLONE (Anavar)
Step 1: Starting with 1-test base, the 3-one is protected as the ethylene ketal as in the above synthesis of methandrostenolone.
Step 2: The 17-OH is oxidized to a 17-one with chomium VI reagent.
step 3: The 17-methyl is attached with methyl magnesium iodide and the crude reaction mixture is treated with water and acid to quench the reaction and remove the ketal protecting group. The product is 17-methyl-1-test.
Step 4: the 17-methy-1-test is treated with ozone in methanol and then NaOH is added. This allows the purification of the intermediate by recrystallization of the sodium salt. The result is that the double bond is cleaved to give a carboxyolic acid (salt) on one side and an aldehyde on the other. The salt is dissolved in water and acidified to pH=4. NaBH4 is added to reduce the intermediate aldehyde. The resulting alcohol will spontaniously close with the carboxylic acid to give the desired lactone ring. The product is oxandrolone.
OXYMETHYLONE (Anadrol)
17-methyl-1-test from above is reduced with lithium in liquid ammonia. The ammonia is carefully evaporated under a dry N2 atmosphere to give a dry, crystalline enolate. The enolate is dissolved in dry THF and treated with N-formylmorpholine to give oxymethylone as the product.
DROMOSTANOLONE propionate (Masterone)
Step 1: 1-test base is reduced with lithium in liquid ammonia. The ammonia is carefully evaporated under a dry N2 atmosphere to give a dry, crystalline enolate. The enolate is dissolved in dry THF and treated with methyl iodide to install the 2-methyl group.
Step 2: the dromostanolone resulting from step 1 is esterified with propanoyl chloride and pyridine to afford the product, masterone.
Krzysztof Piekarz
VLAD.IV
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AnimalStak
Dj_Smalec
-Szoho-
